Find the 6 digit palindrome divisible by 55. (2024)

FAQs

What is a 6 digit palindrome number? ›

A number is called a palindrome if it reads the same backward as well as forward. For example 285582 is a six digit palindrome.

Fourth, 55 is a palindrome number since it reads the same forward or backward.

So we have a - b + c - c +b -a which does equal 0. This means that all numbers of this form are divisible by 11 so there are 9*10*10 = 900 six digit palindromic numbers that are divisible by 11.

If you're looking for a palindrome that is wholely divisible by 6, then 89898 is your answer.

A palindrome number is a number that reads the same forward and backward. In other words, if you reverse the digits of a palindrome number, you get the same number. For example, 121 is a palindrome number because if you read it backward, it is still 121. Another example of a palindrome number is 132231.

56 becomes palindromic after one iteration: 56+65 = 121. 57 becomes palindromic after two iterations: 57+75 = 132, 132+231 = 363. 59 becomes a palindrome after three iterations: 59+95 = 154, 154+451 = 605, 605+506 = 1111.

0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 22, 33, 44, 55, 66, 77, 88, 99, 101, 111, 121, 131, 141, 151, 161, 171, 181, 191, 202, ... (sequence A002113 in the OEIS). Palindromic numbers receive most attention in the realm of recreational mathematics.

9*10*10*1*1 = 900 5-digit palindromes are possible. Here is the list: 10001 10101 10201 10301 10401 10501 10601 10701 10801 10901 11011 11111 11211 11311 11411 11511 11611 11711 11811 11911 12021 12121 12221 12321 12421 12521 12621 1.

The number 210012 satisfies both conditions, so it is the smallest six-digit palindrome divisible by 12.

How many 6 digit palindromes are divisible by 9? ›

There are (999–99)/9 = 100 such numbers. A nice even 100 6-digit palindromes are divisible by 9.

Therefore, the largest five-digit palindrome which is divisible by 6 is 89898. 3.

Hence there are 9×10×10=900 9 × 10 × 10 = 900 possible six-digit palindromes. 9091a+910b+100c.

So, we have 4*10*10*1*1*1 = 400 different 6 digit even palindromes.

Divisibility Rule of 6

Numbers which are divisible by both 2 and 3 are divisible by 6. That is, if the last digit of the given number is even and the sum of its digits is a multiple of 3, then the given number is also a multiple of 6. Example: 630, the number is divisible by 2 as the last digit is 0.

For example: To the number 562 there are 56265 and 562265. You can conclude that there are 900 palindromes withfive and 900 palindromes with six digits. You have 9+9+90+90+900+900 = 1998 palindromes up to one million.

It should be 729. A 6-digit palindrome is just a 3-digit number that is reversed and appended to the 3- digit number so your question is equivalent to how many 3-digit numbers do not contain a 0. The 100s digit can be 1–9, same for the 10s digit and the 1s digit. That means there are 9x9x9 = 729 combinations.

What is the maximum number of 6 letter palindromes? - Quora. The answer to your question is 17,576. There are 26 letters in the alphabet. Once you fill the first three spots the remaining three are forced.

The highest six-digit palindrome that is a multiple of six is 891198. 891198 is ix digit number. It is multiple by six. So it is Largest 6-digit palindrome which is a multiple of 6.